Which of the following pairs indicates the correct oxidation states for Tin?

Study for the ALEKS Placement Chemistry Exam. Review flashcards and multiple choice questions, each with hints and explanations. Get ready for your chemistry exam!

Tin can exhibit different oxidation states depending on the compound it forms. The common oxidation states for tin are +2 and +4.

When tin is in the +2 oxidation state (Sn²⁺), it typically forms compounds like tin(II) chloride (SnCl₂). In this state, tin loses two electrons. On the other hand, in the +4 oxidation state (Sn⁴⁺), it has lost four electrons, allowing it to form compounds like tin(IV) oxide (SnO₂).

These oxidation states are significant in determining the properties and reactivity of tin in chemical reactions. Therefore, the pair Sn(2+) and Sn(4+) accurately reflects the common and stable oxidation states of tin, making it the correct answer.

The other options contain oxidation states that are less commonly encountered or incorrect for tin. For example, Sn(1+) and Sn(5+) do not represent stable or well-documented oxidation states for tin.

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